# Craig’s theorem (1953)

Proof concerning the formal description of scientific theories, expounded by William Craig.

According to Craig, a formal expression of a scientific theory is divisible into ‘theoretical’ and ‘observational’ vocabularies, and (since the ‘observational’ terms are all deducible) it follows that a description can be produced that consists only of ‘observational’ terms and in which all ‘theoretical’ terms are omitted (although he did not suggest that these were in fact undesirable).

In mathematical logic, Craig’s theorem states that any recursively enumerable set of well-formed formulas of a first-order language is (primitively) recursively axiomatizable. This result is not related to the well-known Craig interpolation theorem, although both results are named after the same logician, William Craig.

## Recursive axiomatization

Let {\displaystyle A_{1},A_{2},\dots } be an enumeration of the axioms of a recursively enumerable set T of first-order formulas. Construct another set T* consisting of

{\displaystyle \underbrace {A_{i}\land \dots \land A_{i}} _{i}} for each positive integer i. The deductive closures of T* and T are thus equivalent; the proof will show that T* is a recursive set. A decision procedure for T* lends itself according to the following informal reasoning. Each member of T* is either {\displaystyle A_{1}} or of the form

{\displaystyle \underbrace {B_{j}\land \dots \land B_{j}} _{j}.} Since each formula has finite length, it is checkable whether or not it is {\displaystyle A_{1}} or of the said form. If it is of the said form and consists of j conjuncts, it is in T* if the (reoccurring) conjunct is {\displaystyle A_{j}} ; otherwise it is not in T*. Again, it is checkable whether the conjunct is in fact {\displaystyle A_{n}} by going through the enumeration of the axioms of T and then checking symbol-for-symbol whether the expressions are identical.

## Primitive recursive axiomatizations

The proof above shows that for each recursively enumerable set of axioms there is a recursive set of axioms with the same deductive closure. A set of axioms is primitive recursive if there is a primitive recursive function that decides membership in the set. To obtain a primitive recursive aximatization, instead of replacing a formula {\displaystyle A_{i}} with

{\displaystyle \underbrace {A_{i}\land \dots \land A_{i}} _{i}} {\displaystyle \underbrace {A_{i}\land \dots \land A_{i}} _{f(i)}} (*)

where f(x) is a function that, given i, returns a computation history showing that {\displaystyle A_{i}} is in the original recursively enumerable set of axioms. It is possible for a primitive recursive function to parse an expression of form (*) to obtain {\displaystyle A_{i}} and j. Then, because Kleene’s T predicate is primitive recursive, it is possible for a primitive recursive function to verify that j is indeed a computation history as required.

## Philosophical implications

If {\displaystyle T} is a recursively axiomatizable theory and we divide its predicates into two disjoint sets {\displaystyle V_{A}} and {\displaystyle V_{B}} , then those theorems of {\displaystyle T} that are in the vocabulary {\displaystyle V_{A}} are recursively enumerable, and hence, based on Craig’s theorem, axiomatizable. Carl G. Hempel argued based on this that since all science’s predictions are in the vocabulary of observation terms, the theoretical vocabulary of science is in principle eliminable. He himself raised two objections to this argument: 1) the new axioms of science are practically unmanageable, and 2) science uses inductive reasoning and eliminating theoretical terms may alter the inductive relations between observational sentences. Hilary Putnam argues that this argument is based on a misconception that the sole aim of science is successful prediction. He proposes that the main reason we need theoretical terms is that we wish to talk about theoretical entities (such as viruses, radio stars, and elementary particles).

### One thought on “Craig’s theorem (1953)”

1. Brook Kostek says:

Hey there, You’ve done an excellent job. I will definitely digg it and personally recommend to my friends. I am confident they’ll be benefited from this web site.